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Pointer with Structure in C

A pointer to a structure stores the address of a structure variable. It allows you to access and modify structure members through the pointer using the arrow operator (->).

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Syntax

struct StructureName *pointer_name;

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Arrow Operator (->)

When accessing members through a pointer, use -> instead of .: 
ptr->member    // equivalent to: (*ptr).member

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Example: Pointer to Structure

#include <stdio.h>

struct Student {
    int roll;
    float marks;
};

int main() {
    struct Student s1 = {101, 89.5};
    struct Student *ptr;

    ptr = &s1;   // ptr holds the address of s1

    printf("Roll  = %d\n",   ptr->roll);
    printf("Marks = %.2f\n", ptr->marks);

    return 0;
}
Output: 
Roll  = 101
Marks = 89.50

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Modifying Members via Pointer

#include <stdio.h>

struct Student {
    int roll;
    float marks;
};

int main() {
    struct Student s1 = {101, 88.5};
    struct Student *ptr = &s1;

    ptr->marks = 95.0f;   // modify through pointer

    printf("Roll  = %d\n",   ptr->roll);
    printf("Marks = %.2f\n", ptr->marks);

    return 0;
}
// Output: Roll = 101  Marks = 95.00

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Dot (.) vs Arrow (->)

SituationOperatorExample
Direct structure variable.s1.roll
Pointer to structure->ptr->roll
Both are equivalent: 
ptr->roll     // using arrow
(*ptr).roll   // using dot after dereferencing — same thing

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Passing Structure Pointer to a Function

#include <stdio.h>

struct Student {
    int roll;
    float marks;
};

void display(struct Student *s) {
    printf("Roll : %d\n",   s->roll);
    printf("Marks: %.2f\n", s->marks);
}

int main() {
    struct Student s1 = {102, 91.5};
    display(&s1);
    return 0;
}
This is the preferred way to pass structures — no copying, direct modification possible.